]Oblicz pole trójkąta równobocznego o boku 4 pierwiastki z 3 podzielić na 3
a = 4 p(3)/3
więc
a^2 = [ 4 p(3) / 3 ]^2 = ( 16*3)/9 = 16/3
Pole
P = a^2 p(3)/4 = ( 16/3) p(3)/4 = ( 4 p(3))/3 = (4/3) p(3)
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p(3) - pierwiastek kwadratowy z 3
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a = 4 p(3)/3
więc
a^2 = [ 4 p(3) / 3 ]^2 = ( 16*3)/9 = 16/3
Pole
P = a^2 p(3)/4 = ( 16/3) p(3)/4 = ( 4 p(3))/3 = (4/3) p(3)
==========================================
p(3) - pierwiastek kwadratowy z 3