oblicz pole trojkąta o wierzchołkach A=(-1.-1) B=(5.-1) c= (1.4) oblicz pole trojkąta o wierzchołkach E=(-4.-2) F= (-4.1) G=(3.3)
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1.
|AB| = 6
h = 5
P = |AB|h/2
P = 6*5 / 2
P = 15
2.
h = |(-4,3)G| = 7
|EF| = 3
P = h*|EF| / 2
P = 7 * 3 / 2
P = 10,5
Pozdrawiam! :D