podstawa =a=12
wysokosc =h
25%=0,25 =¼
12·¼=3dm
h=a-3=12-3=9dm
Pole trojkata wynosi zatem :
PΔ=½·a·h=½·12dm·9dm=54dm²
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podstawa =a=12
wysokosc =h
25%=0,25 =¼
12·¼=3dm
h=a-3=12-3=9dm
Pole trojkata wynosi zatem :
PΔ=½·a·h=½·12dm·9dm=54dm²