Oblicz pole trojkata rownobocznego wpisanego na okregu o promieniu 8 cm.
r = 2/3h4 = 2/3h12 = 2hh=6 h = (aV3)/26 = (av3)/212 = aV3a = 12/V3a = 4V3P = (a^2V3)/4P = 4V3V3 = pierwiastek z trzech u mnie, pozdro
Trójkąt w kole.
r=8
r=1/3h
h=3r
h=3 * 8=24
h=a√3÷2
a=2h÷√3
a=2*24 ÷√3=48 / √3 ·√3 / √3=48√3/3=16√3
P=a²√3÷4
P=(16√3)² √3 ÷4=192√3
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r = 2/3h
4 = 2/3h
12 = 2h
h=6
h = (aV3)/2
6 = (av3)/2
12 = aV3
a = 12/V3
a = 4V3
P = (a^2V3)/4
P = 4V3
V3 = pierwiastek z trzech u mnie, pozdro
Trójkąt w kole.
r=8
r=1/3h
h=3r
h=3 * 8=24
h=a√3÷2
a=2h÷√3
a=2*24 ÷√3=48 / √3 ·√3 / √3=48√3/3=16√3
P=a²√3÷4
P=(16√3)² √3 ÷4=192√3