oblicz pole trapezu:
1.. a=4,3cm b=5,7cm h=35cm
2. a=1km b=3km h=0,5km
P=½(a+b)×h1. P=½(4,3+5,7)×35=½×10×35=5×35=175cm²2. P=½(1+3)×0,5=½×4×0,5=1km²
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P=½(a+b)×h
1. P=½(4,3+5,7)×35=½×10×35=5×35=175cm²
2. P=½(1+3)×0,5=½×4×0,5=1km²