oblicz pole trapezu w którym wysokosc ma 1.5 dm a suma podstaw jest 2 razy dłuższa od wysokosci.
p=0.5*(a+b)*h p=0.5*3dm*1.5dm p=2.25dm²
a+b=2*h=2*1,5dm=3dm
h=1,5dm
P=(a+b):2*h
P=3dm:2*1,5dm
P=1,5dm*1,5dm
P=2,25dm²
pole trapezu wynosi 2,25dm²
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p=0.5*(a+b)*h
p=0.5*3dm*1.5dm
p=2.25dm²
a+b=2*h=2*1,5dm=3dm
h=1,5dm
P=(a+b):2*h
P=3dm:2*1,5dm
P=1,5dm*1,5dm
P=2,25dm²
pole trapezu wynosi 2,25dm²