Oblicz pole rombu o boku 4 cm i dłuższej przekątnej równej 4 pierwiastek z 3
a = 4cm
d1 = 4√3cm
(1/2d1)² + (1/2d2)² = a²
(2√3)² + 1/4d2² = 4²
1/4d2² = 16 - 12
1/4d2² = 4 /*4
d2² = 16
d2 = 4cm
P = 1/2 * d1 * d2
P = 1/2 * 4√3 * 4
P = 8√3 cm² --------- odpowiedź
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a = 4cm
d1 = 4√3cm
(1/2d1)² + (1/2d2)² = a²
(2√3)² + 1/4d2² = 4²
1/4d2² = 16 - 12
1/4d2² = 4 /*4
d2² = 16
d2 = 4cm
P = 1/2 * d1 * d2
P = 1/2 * 4√3 * 4
P = 8√3 cm² --------- odpowiedź