Oblicz pole rombu którego przekątne są równe 17dm i 22dm
P=e*f/2
e=17dm
f=22dm
P=?
P=17*22/2
P=187 dm2
p=17*22/2 = 187dm2
Odp. Pole tego rombu wynosi 187 dm2.
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P=e*f/2
e=17dm
f=22dm
P=?
P=17*22/2
P=187 dm2
P=e*f/2
e=17dm
f=22dm
p=17*22/2 = 187dm2
Odp. Pole tego rombu wynosi 187 dm2.