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πr²=25π
r²=25
r=5
2r=2*5=10
H=8
Pp=2r*H
Pp=10*8=80 [j²]
IIr^2 = 25II
r^2 = 25
r = 5cm
H =8
Przekrój to prostokat o długościach boków H i 2r
H = 8 cm
2r = 10 cm
Pole = 8*10 = 80 cm^2
(^) potega