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h=5a
h=5*3[cm]h=15[cm]
P=(1/2)ah pole pow. trojkata
P=(1/2)*3*15[cm²]
P=22,5[cm²]
Pole pow. tego trojkata wynosi 22,5[cm²]
a = 3cm
h = 3cm x 5
h = 15cm
P = (3cm x 15cm)/2
P = 45cm/2
P = 22,5cm kwadratowych (taka dwójka u góry po cm)