Oblicz pole powierzchni trapezu o podstawach rownych 7cm i 5cm oraz wysokosci 3cm
a=7cm
b=5cm
h=3cm
P=(a+b)h/2
P=(7+5)*3/2=12*3/2=6*3=18cm²
P=(7cm+5cm)·3cm:2=12cm·3cm:2=36cm:2=18cm
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a=7cm
b=5cm
h=3cm
P=(a+b)h/2
P=(7+5)*3/2=12*3/2=6*3=18cm²
P=(7cm+5cm)·3cm:2=12cm·3cm:2=36cm:2=18cm