oblicz pole powierzchni kwadratu o obwodzie 96m. zamień na m2 i a .
oblicz pole rombu o przekątnych 24 cm i 10 cm
kwadrat ma 4 boki
96:4 = 24 m = a - długość boku
Pole
P = a^2
P = 24^2
P = 576 m^2
P = 576 : 100 = 5,76 a
Romb
e = 24 cm
f = 10 cm
P = (e*f)/2
P = 24*10/2
P = 240/2
P = 120 cm^2
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kwadrat ma 4 boki
96:4 = 24 m = a - długość boku
Pole
P = a^2
P = 24^2
P = 576 m^2
P = 576 : 100 = 5,76 a
Romb
e = 24 cm
f = 10 cm
P = (e*f)/2
P = 24*10/2
P = 240/2
P = 120 cm^2
kwadrat ma 4 boki
96:4 = 24 m = a - długość boku
Pole
P = a^2
P = 24^2
P = 576 m^2
P = 576 : 100 = 5,76 a
Romb
e = 24 cm
f = 10 cm
P = (e*f)/2
P = 24*10/2
P = 240/2
P = 120 cm^2