oblicz pole powierzchni kuli, ktore objetosc wynosi 36000(pi)
V=36000π
4/3πr³ =36000π /:π
4/3r³=36000
r³=36000 · 3/4
r³=27000
r=∛2700
r=30
P=4πr² =30²·4π =900·4π =3600π j.²
P =4πr2V= 4/3 πr336000π =4/3 πr336000=4/3r3 / *3108000=4r3 / :4r3= 27000r= 30 P= 4*π30 2P= 4*π900P= 3600π
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V=36000π
4/3πr³ =36000π /:π
4/3r³=36000
r³=36000 · 3/4
r³=27000
r=∛2700
r=30
P=4πr² =30²·4π =900·4π =3600π j.²
P =4πr2
V= 4/3 πr3
36000π =4/3 πr3
36000=4/3r3 / *3
108000=4r3 / :4
r3= 27000
r= 30
P= 4*π30 2
P= 4*π900
P= 3600π