oblicz pole powierzchni czworościanu foremnego o krawędzi 2pierwiastki z 5 cm.
a=2V5cm
Pc=a^2V3
Pc=(2V5)^2*V3=4*5V3
Pc=20V3cm^2
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a=2V5cm
Pc=a^2V3
Pc=(2V5)^2*V3=4*5V3
Pc=20V3cm^2