Oblicz pole powierzchni całkowitej oraz objętość prostopadłoscianu o wymiarach podstawa 2 cm i1 .5 cm wys 1 cm
a=2cm
b=1,5cm
c=1cm
Pc=2pp+Pb
Pc=2*a*b+2*a*c+2*b*c
Pc=2*2cm*1,5cm+2*2cm*1cm+2*1,5cm*1cm
Pc=6cm²+4cm²+3cm²
Pc=13cm²
V=abc
V=2cm*1,5cm*1cm
V=3cm³
objetosc to V
V=a*b*c
V=2*1*1,5=3 [cm ²]
p=2(a*b+b*c+c*a)
p=2(1*1,5+2*1+1,5*2)=2*6,5=13 [cm]
licze na naj :)
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a=2cm
b=1,5cm
c=1cm
Pc=2pp+Pb
Pc=2*a*b+2*a*c+2*b*c
Pc=2*2cm*1,5cm+2*2cm*1cm+2*1,5cm*1cm
Pc=6cm²+4cm²+3cm²
Pc=13cm²
V=abc
V=2cm*1,5cm*1cm
V=3cm³
objetosc to V
V=a*b*c
V=2*1*1,5=3 [cm ²]
p=2(a*b+b*c+c*a)
p=2(1*1,5+2*1+1,5*2)=2*6,5=13 [cm]
licze na naj :)