zad
a=20cm
h=5√3cm
a)trojkatnego:
Pc=2Pp+3Pb=2·20²√3:4+3·20·5√3=200√3+300√3=500√3cm²
b)czworokatnego:
Pc=2Pp+4Pb=2·20²+4·20·5√3=800+400√3=400(2+√3)cm²
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zad
a=20cm
h=5√3cm
a)trojkatnego:
Pc=2Pp+3Pb=2·20²√3:4+3·20·5√3=200√3+300√3=500√3cm²
b)czworokatnego:
Pc=2Pp+4Pb=2·20²+4·20·5√3=800+400√3=400(2+√3)cm²