Oblicz pole koła wpisanego w trójkat rownoboczny o boku dlugosci 10m
h²= 10² - 5²
h² = 100-25
h²= 75 /: √
h= 5√3
r= ⅓ h
r= ⅓ * 5√3
r= 5√3 : 3
P= pi *r²
p= π * ( 5√3:3)²
p= 25 π
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h²= 10² - 5²
h² = 100-25
h²= 75 /: √
h= 5√3
r= ⅓ h
r= ⅓ * 5√3
r= 5√3 : 3
P= pi *r²
p= π * ( 5√3:3)²
p= 25 π