Oblicz pole koła o punkcie s
r^2 = 4^2 + ( r - 3)^2
r^2 = 16 + r^2 - 6r + 9
6r = 25
r = 25/6
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Pole
P = pi *r^2 = pi* (25/6)^2 = ( 625/36) *pi
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r^2 = 4^2 + ( r - 3)^2
r^2 = 16 + r^2 - 6r + 9
6r = 25
r = 25/6
=========
Pole
P = pi *r^2 = pi* (25/6)^2 = ( 625/36) *pi
==================================