Oblicz pole koła o obwodzie 4 <pi> cm. Prosze pomóżcie. :)
L=2πr
4π=2πr
4=2r
r=2[cm]
P=πr²
P=2²π
P=4π[cm]
P= IIr^2
Obw= 2IIr
4II=2IIr /:2
2II=IIr /:II
2=r
sprawdzenie- obw=2II*2= 4II
Pole= II*2^2
p= 4II
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L=2πr
4π=2πr
4=2r
r=2[cm]
P=πr²
P=2²π
P=4π[cm]
P= IIr^2
Obw= 2IIr
4II=2IIr /:2
2II=IIr /:II
2=r
sprawdzenie- obw=2II*2= 4II
Pole= II*2^2
p= 4II