Oblicz pole koła którego obwód jest równy 39,56 cm
2πr=39,56cm
2*3,14*r=39,56 /:3,14
2r=12,6cm
r=6,3cm
P=πr²
P=3,14*6,3²=3,14*39,69=124,63cm²
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2πr=39,56cm
2*3,14*r=39,56 /:3,14
2r=12,6cm
r=6,3cm
P=πr²
P=3,14*6,3²=3,14*39,69=124,63cm²