oblicz pole i obwod trapezu o podstawach 8 i 12.katy ostre trapezu maja miare 30 i 45 stopni
wysokosc
h√3+h=12-8
h(√3+1)=4
h=4/(√3+1)=4(√3-1)/(3-1)=4(√3-1)/2=2(√3-1)=2√3-2
pole
(8+12)(2√3-2)/2=20(2√3-2)/2=10(2√3-2)=20√3-20
obwod
8+12+2(2√3-2)+√2(2√3-2)=20+4√3-4+2√6-2√2=16-2√2+4√3+2√6=2(8-√2+2√3+√6)
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wysokosc
h√3+h=12-8
h(√3+1)=4
h=4/(√3+1)=4(√3-1)/(3-1)=4(√3-1)/2=2(√3-1)=2√3-2
pole
(8+12)(2√3-2)/2=20(2√3-2)/2=10(2√3-2)=20√3-20
obwod
8+12+2(2√3-2)+√2(2√3-2)=20+4√3-4+2√6-2√2=16-2√2+4√3+2√6=2(8-√2+2√3+√6)