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Obliczamy pola tych wielokątów za pomocą znanych wzorów, potem dodajemy.
P₁ = = = 3,5
P₂ = = = = 19,5
P₃ = ah = 6 · 3 = 18
3,5 + 19,5 + 18 = 41
Odp. Pole figury wynosi 41 [ j² ]