oblicz Pole całkowite i objętośc prostopadłościanu o wymiarach 3 na 6 na 10
a=3
b=6
c=10
V=abc=3*6*10
V=180 j3
P=2ab+2bc+2ac=2*3*6+2*6*10+2*3*10
P=216 j2
a = 3
b = 6
c = 10
V=3*6*10=180 [j³]
P= 2ab+2bc+2ac=2*3*6+2*6*10+2*3*10 = 216 [j²]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a=3
b=6
c=10
V=abc=3*6*10
V=180 j3
P=2ab+2bc+2ac=2*3*6+2*6*10+2*3*10
P=216 j2
a = 3
b = 6
c = 10
V=3*6*10=180 [j³]
P= 2ab+2bc+2ac=2*3*6+2*6*10+2*3*10 = 216 [j²]