Oblicz pola trójkątów :
a) x to bok przeciwko kątowi 45 stopni
x=10
Podstawa = 2x = 20
P= (a*h)/2 = (20*10)/2 = 100 j²
a= 4+3 = 7
P= (a*h)/2 = (7*3)/2 = 21/2 = 10,5 j²
b) P= (a*h)/2 = (0,3 * 0,4)/2= 0,12/2= 0,06j²
P1= (4*3)/2 = 6
P2= (3*3)/2 = 4,5
P1 + P2 = 6+4,5=10,5
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a) x to bok przeciwko kątowi 45 stopni
x=10
Podstawa = 2x = 20
P= (a*h)/2 = (20*10)/2 = 100 j²
a= 4+3 = 7
P= (a*h)/2 = (7*3)/2 = 21/2 = 10,5 j²
b) P= (a*h)/2 = (0,3 * 0,4)/2= 0,12/2= 0,06j²
P1= (4*3)/2 = 6
P2= (3*3)/2 = 4,5
P1 + P2 = 6+4,5=10,5