Oblicz pH roztworu 0,2 molowego roztworu kwasu azotowego (III) zdysocjowanego w 5%
Oblicz pH roztworu 0,2 molowego roztworu kwasu azotowego (III) zdysocjowanego w 5%
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Cm =
alfa = 5% = 0,05
Cz=![[H^+]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D "[H^+]")
0,05=![\frac{[H^+]}{0,2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH%5E%2B%5D%7D%7B0%2C2%7D "\frac{[H^+]}{0,2}")
pH = - log![[H^+]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D "[H^+]")
pH = - log
= 2