Oblicz Pc ostrosłupa prawidłowego trójkątnego o wymiarach a=13cm hp=6cm hb=23cm. pomóżcie plisss
13*6/2=78/2=39=Pp
13*23/2=299/2=149,5=Pb
39+(149,5*3)=39+448,5=487,5=Pc
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13*6/2=78/2=39=Pp
13*23/2=299/2=149,5=Pb
39+(149,5*3)=39+448,5=487,5=Pc