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dany Δ ma boki a=8cm b=12cm c=14cm
to jego obwod O=a+b+c=8+12+14=34cm
Δ podobny w skali k=3/4 ma obwod
O₂/O=k
O₂/34=3/4
4·O₂=3·34
4O₂=102
O₂=102:4=25½ cm--->odpowiedz