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a, b - boki prostokąta, gdzie
a = 2b
z Twierdzenia Pitagorasa:
5^2 = b^2 + a^2
5^2 = b^2 + (2b)^2
5^2 = b^2 + 4b^2
5^2 = 5b^2
5 * 5 = 5 * b^2 /5
5 = b^2
b = pierwiastek (5)
a = 2*b = 2 * pierwiastek (5)
OBWÓD:
2a + 2b = 2 * pierwiastek (5)+ 2* (2 * pierwiastek (5)) = 6 * pierwiastek (5)