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r=4
L=2*pi*r
L=2*pi*4cm
L=8pi cm
więc:
16πcm²= πr² /: π
r²= 16 cm²
r= 4 cm
Obwód koła- 2πr
2π × 4cm = 8π cm
o polu:16 π cm kwadratowych?
P=16π cm²
P=πr²
πr²=16π
r²=16
r=√16
r=4
Obw=2πr
Obw=2*π*4
Obw=8π