Oblicz objętość i pole całkowite graniastosłupa trójkątnego prawidłowego. H- 10 a-6
Dane :
a= 6
H = 10
Pc = 2Pp + Pb
Pp= a²Ѵ3/4
Pp = 6²Ѵ3/4 = 36Ѵ3/4 = 9Ѵ3
Pb= 3a*H
Pb = 3 * 6 * 10 = 180
Pc= 2 * 9Ѵ3 + 180 = 18Ѵ3 +180 = 18(Ѵ3 + 10) [j²]
V=Pp*H
V = 9Ѵ3 * 10 = 90Ѵ3 [j³]
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Dane :
a= 6
H = 10
Pc = 2Pp + Pb
Pp= a²Ѵ3/4
Pp = 6²Ѵ3/4 = 36Ѵ3/4 = 9Ѵ3
Pb= 3a*H
Pb = 3 * 6 * 10 = 180
Pc= 2 * 9Ѵ3 + 180 = 18Ѵ3 +180 = 18(Ѵ3 + 10) [j²]
V=Pp*H
V = 9Ѵ3 * 10 = 90Ѵ3 [j³]