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V=pole podstawy * wysokość
1
Pp= pole trojkata
a=5
b=12
H = 16
V=(5*12):0.5 * 16 =480 cm3
2.
Pp=pole trapezu
a=6
b=10
ht =3
H=17
V=( (6+10)*3 ):0.5 * 17 =24*16=408