Oblicz objętość CO2, która powstaje w wyniku spalenia 300g etanu.
2C2H6+7O2---->4CO2+6H2O
300g V=?
2mC2H6=4*12u+12*1u=60u
4mCO2=4*12u+8*16u=176u
60u-----300g
176u-----x
x=880g CO2
d=m/V
dCO2=1,97g/dm3
V=m/d
V=880g/1,97g/dm3
V=446,7dm3
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
2C2H6+7O2---->4CO2+6H2O
300g V=?
2mC2H6=4*12u+12*1u=60u
4mCO2=4*12u+8*16u=176u
60u-----300g
176u-----x
x=880g CO2
d=m/V
dCO2=1,97g/dm3
V=m/d
V=880g/1,97g/dm3
V=446,7dm3