Oblicz objętość bryłki mtalu o masie 10g wykonanej z: glinu, żelaza i ołowiu
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v=m/d
1) glin
d=2.7g/cm3
v=10g/2,7g/cm3
v=3.70 cm3= 0,0037 dm3
2)ołów
d=11.4 g/cm3
v=10g/11.4g/cm3
v=0.877cm3= 0.00087 dm3
3) żelazo
d=7.9g/cm3
v=10g/7.9g/cm3
v=1.27cm3 = 0.00127 dm3