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CO + 3H₂--->H₂O+CH₄
4dm³ x
x=4*22,4/22,4+67,2=1dm³
4*22.4dm3 (CO i H2) - 22.4dm3 CH4
4dm3 - xdm3
x= 1dm3 metanu
w zadaniu założyłam warunki normalne