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walec objętość stożek objętość
V=πr²H V=⅓πr²H
V=π*4²*3 V=⅓π*4²*5(80:3)
V=48π V=26π
SUMA OBJĘTOŚCI WYNOSI 74π
walec pole stożek pole
Pc=2πr²+2πrH Pc= πr²+πrH
Pc=2*π*4²+2π4*5 pc=π4²+π4*5
Pc=32π+ 40π Pc= 36π
Pc=72π
suma wynosi 108π