oblicz moc pompy która w ciągu 1min wypompowywuje240 kg wody ze studni o głembokośći 20m
t = 1 min = 60 s
h = 20 m
m = 240 kg
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F = m*g
Praca
W = F*h = m*g*h
W = 240 kg * 10 m/s^2 *20 m = 48 000 J
Moc
P = W / t
P = 48 000 J : 60 s = 800 W
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t = 1 min = 60 s
h = 20 m
m = 240 kg
------------------------
F = m*g
Praca
W = F*h = m*g*h
W = 240 kg * 10 m/s^2 *20 m = 48 000 J
Moc
P = W / t
P = 48 000 J : 60 s = 800 W
==============================