oblicz moc pompy która w ciągu 2min wypompowywuje 360 kg wody ze studni o głebokości 20m
Dane:
t = 2 min. - 120 s
m = 360 kg
h = 20 m
g = 10m/s^2
P = ?
P = W/t
W = Ep = mgh
P = mgh/t
P = 360*10*20/120
P= 600 W
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Dane:
t = 2 min. - 120 s
m = 360 kg
h = 20 m
g = 10m/s^2
P = ?
P = W/t
W = Ep = mgh
P = mgh/t
P = 360*10*20/120
P= 600 W