Question

Oblicz masy nastepujacych tlenkow a)N2O5 b)SO3 c)Na2O

Answer 1

a)

MN= 14 u

MO= 16 u

M= 2 * 14 u + 5 * 16u

M= 28u + 80 u

M= 108 u

b)

MS= 32 u

MO= 16 u

M= 32u+ 3* 16u

M= 32 u + 48u

M= 80 u

c) 

MNa= 23 u

MO= 16 u

M= 2 * 23 u + 16u

M= 46u + 16u

M= 62 u

Answer 2

2N = 2*14=28u

5O = 5*16=80u

___________

m N2O5 = 108u

 

SO3

 

S= 32u

3O = 3*16 =48u

____________

m SO3 = 80u

 

Na2O

 

2Na = 2*23 = 46u

O= 16u

____________

 

m Na2O = 62u