Oblicz masy cząsteczkowe związków:
Mg3(PO4)2=
KNO3=
HBr=
H2SO4=
bardzo proszę o działanie a nie o sam wynik;p
H2SO4= 2x1u + 1x32u +4x16u = 2u + 32u + 64u = 98u
HBr = 1u + 80u = 81u
KNO3 = 39u + 14u + 3x16u = 39u + 14u + 48u = 101u
Są 3 z 4.
Mg3(PO4)2=3*24u 2(31u 4*16u) = 72u 62u 2*64u = 262u
KNO3 = 39u + 14u + 48u = 101u
HBr=1u + 80u = 81u
H2So4= 2 · 1u + 32u + 4 · 16u = 98u
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H2SO4= 2x1u + 1x32u +4x16u = 2u + 32u + 64u = 98u
HBr = 1u + 80u = 81u
KNO3 = 39u + 14u + 3x16u = 39u + 14u + 48u = 101u
Są 3 z 4.
Mg3(PO4)2=3*24u 2(31u 4*16u) = 72u 62u 2*64u = 262u
KNO3 = 39u + 14u + 48u = 101u
HBr=1u + 80u = 81u
H2So4= 2 · 1u + 32u + 4 · 16u = 98u