Question

Oblicz masy cząsteczkowe podanych związków oraz oblicz ich skład procentowy : H2O N2O5 Cu2O SO3

Answer 1

H20 =  2*1u + 16u = 2u + 16u = 18u
%H = 2/18 * 100% = 11,11%
%0= 16/18 * 100% = 88,89%
N205 =   2*14u + 5*16u = 28u + 80u = 108u
%N = 28/108 * 100% = 25,93
% 0 = 80/108 *100% = 74,07
  Cu20 =   2*63,5u + 16u = 127u + 16u = 143u
%Cu=  127/143*100% =  88,81%
%0= 16/143*100% = 11,19%
  S03 =    32u + 3*16u = 32u + 48u = 80u
%S= 32/80 *100% = 40%
%0= 48/80*100% = 60%

Answer 2

= 2*1u + 16u = 2u + 16u = 18u
= 2*14u + 5*16u = 28u + 80u = 108u
= 2*63,5u + 16u = 127u + 16u = 143u
= 32u + 3*16u = 32u + 48u = 80u