Oblicz masy cząsteczkowe podanych związków chemicznych.
CuO =
Fe₂O₃ =
Na₂CO₃=
H₂SO₄=
Ca(OH)₂=
Fe₂(SO₃)₃=
Oblicz masy cząsteczkowe podanych związków chemicznych.
CuO =
Fe₂O₃ =
Na₂CO₃=
H₂SO₄=
Ca(OH)₂=
Fe₂(SO₃)₃=
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CuO = 64u+16u=80u
Fe₂O₃ = 56u*2+16u*3=112u+48u=160u
Na₂CO₃= 23u*2+12u+16u*3=46u+12u+48u=106u
H₂SO₄= 1u*2+32u+16u*4=2u+32u+64u=98u
Ca(OH)₂= 41u+16u*2+1u*2=41u+32u+2u=75u
Fe₂(SO₃)₃= 56u*2+32u*3+16u*9=112u+96u+144u=352u
CuO =64u+16u=80u
Fe₂O₃ =2*56u+3*16u=112u+48u=160u
Na₂CO₃=2*23u+12u+3*16u=46u+12u+48u=106u
H₂SO₄=2*1u+32u+4*16u=2u+32u+64u=98u
Ca(OH)₂=40u+2*16u+2*1u=40u+32u+2u=74u
Fe₂(SO₃)₃=2*56u+3*32u+9*16u=112u+96u+144u=352u