Question

Oblicz masy cząsteczkowe podanych związków chemicznych :

Na2S , Fe(OH)3 , Mg3(PO4)2 , H2CO3 , Zn(NO3)2.

Answer 1

Na₂S=2*23u+32u=46u+32u=78u

Fe(OH)₃=56u+3*16u+3*1u=56u+48u+3u=107u

Mg₃(PO₄)₂=3*24u+2*31u+8*16u=72u+62u+128u=262u

H₂CO₃=2*1u+12u+3*16u=2u+12u+48u=62u

Zn(NO₃)₂=65u+2*14u+6*16u=65u+28u+96u=189u

Answer 2

Na2S = (23u * 2) + 32u = 46u + 32 u = 78 u
Fe(OH)3 = 55u + (16u + 1u)*3 = 55u + 51u = 106u
Mg3(PO4)2 = (24 u * 3) + [31u + (16*4) * 2 ] = 72u + (31u + 64u * 2) = 72u + 190u = 262u

H2CO3 = 2u + 12u + 48u = 62u
Zn(NO3)2 = 65u + (14u + 48u * 2) = 65u + 124u = 189u