OBLICZ MASY CZĄSTECZKOWE NASTĘPUJĄCYCH ZWIĄZKÓW:
A3PO4
CaCO3
Mg(OH)2
Al2(SO4)3
CH3COOH
Ag₃PO₄ = 3*108u + 31u + 4*16u= 419u
CaCO₃= 40u + 12u + 3*16u = 100u
Mg(OH)₂= 24u + 2*(16u+1u)= 58u
Al₂(SO₄)₃ = 2*27u + 3*(32u + 4*16u) = 342u
CH₃COOH= 12u + 3*1u + 12u + 2*16u + 1u= 60u
A3PO4 (Nie ma A, przypuszczam, że chodziło o Al)
27*3 + 31 + 16*4 = 81 + 31 + 64 = 176 u
40 + 12 + 16*3 = 40 + 12 + 48 = 100 u
24 + 2*(16+1) = 24+ 2*17 = 24 + 34 = 58 u
2*27 + 3*(32 + 4*16) = 54 + 3*(32 + 64) = 54 + 3*96= 54 + 288 = 342 u
12 + 3*1 + 12 + 16 + 16 + 1 = 12 + 3 + 12 + 16 + 16 + 1 = 60 u
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Ag₃PO₄ = 3*108u + 31u + 4*16u= 419u
CaCO₃= 40u + 12u + 3*16u = 100u
Mg(OH)₂= 24u + 2*(16u+1u)= 58u
Al₂(SO₄)₃ = 2*27u + 3*(32u + 4*16u) = 342u
CH₃COOH= 12u + 3*1u + 12u + 2*16u + 1u= 60u
A3PO4 (Nie ma A, przypuszczam, że chodziło o Al)
27*3 + 31 + 16*4 = 81 + 31 + 64 = 176 u
CaCO3
40 + 12 + 16*3 = 40 + 12 + 48 = 100 u
Mg(OH)2
24 + 2*(16+1) = 24+ 2*17 = 24 + 34 = 58 u
Al2(SO4)3
2*27 + 3*(32 + 4*16) = 54 + 3*(32 + 64) = 54 + 3*96= 54 + 288 = 342 u
CH3COOH
12 + 3*1 + 12 + 16 + 16 + 1 = 12 + 3 + 12 + 16 + 16 + 1 = 60 u