oblicz mase molowa substancji np:
MHNO3
MHCL
MH2SO4
MMGO
MH3PO4
MCU(NO3)2
MAL(OH)3
M HNO3 = 16*3+14+1= 63g
M HCl = 36,5g
M H2SO4 = 98g
M MgO = 40g
M H3PO4 = 98g
M Cu(NO3)2 = 64+124 = 188g
M Al(OH)3 = 78g
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M HNO3 = 16*3+14+1= 63g
M HCl = 36,5g
M H2SO4 = 98g
M MgO = 40g
M H3PO4 = 98g
M Cu(NO3)2 = 64+124 = 188g
M Al(OH)3 = 78g