Oblicz masę wodorotlenku sodu zużytego na zobojętnienie kwasu siarkowego (VI) w ilości 294g.
mNaOH=40u
mH2SO4=98u
2NaOH + H2SO4---->Na2SO4 + 2H2O
80g NaOH-----98g H2SO4
xg NaOH-------294g H2SO4
x = 240g NaOH
2NaOH+H2SO4---->Na2SO4+2H2O80g ----- 98gx ------ 294g x=240g NaOH
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mNaOH=40u
mH2SO4=98u
2NaOH + H2SO4---->Na2SO4 + 2H2O
80g NaOH-----98g H2SO4
xg NaOH-------294g H2SO4
x = 240g NaOH
2NaOH+H2SO4---->Na2SO4+2H2O
80g ----- 98g
x ------ 294g
x=240g NaOH