Oblicz masę cząsteczkową:
1. 2Ca(OH)₂
2. 5H₂CO₃
Opisać dokładnie, krok po kroku co się robi.
a)
m(2Ca(OH)₂)=2·(40u+2·(16u+1u))=2·(40u+2·17u)=2·(40u+34u)=2·74u=148u
b)
m(5H₂CO₃)=5·(2·1u+12u+3·16u)=5·(2u+12u+48u)=5·62u=310u
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a)
m(2Ca(OH)₂)=2·(40u+2·(16u+1u))=2·(40u+2·17u)=2·(40u+34u)=2·74u=148u
b)
m(5H₂CO₃)=5·(2·1u+12u+3·16u)=5·(2u+12u+48u)=5·62u=310u