Oblicz masę czasteczkową i zawartość procentową węgla w cząsteczce :
1. tlenku wegla IV
2. etanu
CO₂
M=12+16*2=44 g/mol
44 - 100%
12 - x%
x=1200:44= 27,27%
C₂H₆
M=12*2+1*6=24+6=30g/mol
30 - 100%
24 - x%
x=2400:30=80%
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CO₂
M=12+16*2=44 g/mol
44 - 100%
12 - x%
x=1200:44= 27,27%
C₂H₆
M=12*2+1*6=24+6=30g/mol
30 - 100%
24 - x%
x=2400:30=80%