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V = 5m x 4m x 3m = 60 m³
w powietrzu jest 78,1% azotu, więc:
78,1% x 60 =0,781 x 60 = 46,86 m³
46,86 x 1,15 kg = 53,889 kg≈ 54 kg
ok. 78 % to azot
V azotu=0,78 *60 m³=46,8 m³
m azotu = 46,8m³*1,15kg/m³ = 53,82 kg