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138g-1mol
x-5moli
x=138*5=690g
b)40g- 1mol
x-0,5 mol
x=40*o,5=20g
c)1 mol-98g
2mole-x
x=98*2=196g
To tyle:P w skrócie
K2CO3=2x39+12g+3x16g=138g/mol
138g - 1mol
x - 5moli
x=138gx5moli/1mol=690g
b) 0,5 mola wapnia
MCa=40g
1 mol - 40g
0.5mola - x
x=0.5molax40g/1mol=20g
c) 2 moli kw. siarkowego (VI)
MH2S04=2x1g+32g+4x16g=98g
98g - 1mol
x - 2mole
x=98gx2mole/1mol=196g