Oblicz masę 10-procentowego roztworu HCl, potrzebnego do zobojętnienia 10 g wodorotlenku sodu.
proszę, to ważne
HCl + NaOH --> NaCl + H2O
masa molowa HCl wynosi 36,5g/mol
masa molowa NaOH wynosi 40g/mol40g NaOH - 36,5g HCl10g NaOH - xx= 9,125g HCl
10% - 9,125g HCl
100% - y
y= 91,25g HCl
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HCl + NaOH --> NaCl + H2O
masa molowa HCl wynosi 36,5g/mol
masa molowa NaOH wynosi 40g/mol
40g NaOH - 36,5g HCl
10g NaOH - x
x= 9,125g HCl
10% - 9,125g HCl
100% - y
y= 91,25g HCl